Find Lcm Hcf Verify Lcm × Hcf = Product of Two Numbers Exercise 1.2 Chapter 1 Real Numbers Maths Class 10 NCERT

Question 2. Find the LCM and HCF of the following pairs of integers and verify that LCM × HCF = product of the two numbers. 26 and 91 (ii) 510 and 92 (iii) 336 and 54 Chapter 1: Real Numbers Maths Class 10 solutions are developed for assisting understudies with working on their score and increase knowledge of the subjects. how to find lCM and HCF using prime factorization method, Find LCM HCF verify LCM × HCF = product of two numbers is solved by our expert teachers. You can get ncert solutions and notes for class 10 chapter 1 absolutely free. NCERT Solutions for class 10 Maths Chapter 1: Real Numbers is very essencial for getting good marks in CBSE Board examinations

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Question 2. Find the LCM and HCF of the following pairs of integers and verify that LCM × HCF = product of the two numbers.
26 and 91 (ii) 510 and 92 (iii) 336 and 54

Answer:

(i)

26        = 2 x 13
91        =7 x 13
HCF    = 13
LCM    =2 x 7 x 13     =182
Product of two value           26 x 91           = 2366
Product of HCF and LCM   13 x 182         = 2366
Hence, product of two numbers = product of HCF × LCM

(ii)

510     = 2 x 3 x 5 x 17
92        =2 x 2 x 23
HCF    =2
LCM    =2 x 2 x3 x 5 x 17 x 23         = 23460
Product of both values        510x92           = 46920
Product of HCF and LCM 2x23460         =46920
Hence, product of two numbers = product of HCF × LCM

(iii)

336     = 2 x 2 x 2 x 2 x 3 x 7
54       = 2 x 3 x 3 x 3
HCF    = 2 x 3                                                = 6
LCM    = 2 x 2 x 2 x 2 x 3 x 3 x 3 x 7           =3024
Product of number               336 x 54         =18144
Product of HCF and LCM   6 x 3024         = 18144
Hence, product of two numbers = product of HCF × LCM